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| ### Operation list L1 = list L2 -> elt-alg^boo ### Description Return `true' iff `L1' contains the same elements as `L2' in the same order, i.e. component-wise. Note: The component-wise test especially implies one of the lists can contain holes at positions beyond the scope of the other list. OTOH, Holes within the scope of both lists have to be holes component-wise. ### Examples L1:=[1,,3,4]; L2:=["foo",,3,4*I,2*I]; L1:=L2; L3:=[1,,3,4]; L4:=[1,,3,4,,,]; L3=L4;
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